IT Lesson

C program to find whether a number is an Armstrong number or not

#include<iostream.h>
#include<conio.h>
#include<math.h>

void main()
{
clrscr();
int n,m=0,x,y;
cout<<"Enter any three digit numnber:";
cin>>n;
y=n;

while(n!=0)
{
x=n%10;
m+=pow(x,3);
n=n/10;
}

if(y==m)
cout<<"The number is an Armstrong number";
else
cout<<"The number is not an Armstrong number";
getch();
}

Posted by Unknown at 8:30 PM

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